In a
party, three boxes are placed at a table. And one of them contains
pure gold. Also each box have a message on its top.
1st
Box's message >> “Gold is not here”
2nd
Box's message >> “Gold is not here”
3rd
Box's message >> “Gold is in the 2nd box”
Only one of the
messages are true (other two are lies).
With only one chance,
could you find the right box?
Answer:
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
..
..
..
..
..
..
...
...
...
....
only one box tells true. So lets calculate,
If
the 1st box is true, then the 2nd box tells
gold is in it (because
says “gold is not here”) and the 3rd
box tells the gold is not in the 2nd box (because it says
“gold is in the 2nd box”) which will never match.
Now,
if the 3rd box is true, the 1st box tells it
has the gold (because its message will false because the 3rd box is true) and 2nd box
also tells it have the gold (because its message is also false because the 3rd box is true) which is also not match because there is only one gold.
At last, if the 2nd box is true(gold is not in 2nd box), then the 3rd box will also match(it tells the 2nd box
not contains the gold because it is false) and 1st box tells it has the gold (because its message is false).
So the 1st box contains the gold and the 2nd box is true.
0 comments:
Post a Comment